ohms
in my car i have a older 500w jensen 2 ch. amp and 2 10"MTX blue thunders (4 ohm resistance) . i was reading it puts out 500x1@4 ohms, and 700x1@2 ohms. so my question is if i run the subs in series with the amp bridged (positive in to 1 sub, negative out to positive of other sub and negative back to amp)that would give me a 2 ohm resistance, right? would everything work correctly? is this a good idea or should i leave it parellel with 500w@4 Ohms?
any advice or imput would help me
any advice or imput would help me
If you run the subs in series you will get an 8 ohm load.
You need to run the 2 subs in parallel to get a 2 ohm load.
Run (+) from amp to (+) of both subs
Run (-) from amp to (-) of both subs
You need to run the 2 subs in parallel to get a 2 ohm load.
Run (+) from amp to (+) of both subs
Run (-) from amp to (-) of both subs
If you wire the subs in parallel you will get a 2 ohm load but you will need to bridge the amp to 2 ohms in order to run it which will mean the amp is essentailly running 1 ohm. Most normal 2 channel amps won't handle 1 ohm.
<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Xsi »</TD></TR><TR><TD CLASS="quote">If you wire the subs in parallel you will get a 2 ohm load but you will need to bridge the amp to 2 ohms in order to run it which will mean the amp is essentailly running 1 ohm. Most normal 2 channel amps won't handle 1 ohm.</TD></TR></TABLE>
Actually this is wrong. Don't worry though because this is the industries fault.
If it says it can handle 700X1 into 2 ohms, then you can supply it with a 2 ohm load. I don't know of any Jensen amplifiers that can handle a 2 ohm bridged load regardless of what it says.
Actually this is wrong. Don't worry though because this is the industries fault.
If it says it can handle 700X1 into 2 ohms, then you can supply it with a 2 ohm load. I don't know of any Jensen amplifiers that can handle a 2 ohm bridged load regardless of what it says.
Wire the subs in series will give a total impedence of 8 ohms.
Wire the subs in parallel will give a total impedence of 2 ohms.
whether or not the amp can handle the 2 ohm load i dont know.
btw...saying 2 ohms resistance is an incorrect statement.
resistance = a circuit containing only purely resistive loads such as electric heating elements. the current and voltage are in phase with each other.
Impedence = the total opposition to current flow when you have loads that are resistive, capacitive and inductive.
Wire the subs in parallel will give a total impedence of 2 ohms.
whether or not the amp can handle the 2 ohm load i dont know.
btw...saying 2 ohms resistance is an incorrect statement.
resistance = a circuit containing only purely resistive loads such as electric heating elements. the current and voltage are in phase with each other.
Impedence = the total opposition to current flow when you have loads that are resistive, capacitive and inductive.
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