i just want confirmation of my dyno result..i want to confirm whether it is WHP n engine hp on the chart..and is my tq really read almost 169ft/lbs?
specs:toda c,ferrea valvetrains & valves.87.2mm stroke in b16a..CTR IM oversized TB 68.5mm.4-1header,PnP b16 head and haltech E6K engine management.any comments..may be

 

Thats some nice WHP! (and TQ)

 

thanks.. running stock 81mm bore ctr piston.

 

Damn those are some nice numbers!
What's your secret for that much torque from a b16 ?????

 

what rods are you using?

 

i dont have secret actually..never realise the Tq.i was a bit disappointed at first with the HP but some one pointed out my tq # then i started to think..thats why i posted it so someone can shed some light on this... b16a block with 87.2mm stroke with deckplate, ctr pistons and pr3 conrods..Pnp head flowbenched...

 

I'd like to see your AFR...

 

I dont think it would be 169ftlbs on a dynojet.Mustve been the way that dyno was setup.I had a 89mm stroke b16a,85mm bore,15:1 compression etc..it made 230whp and only made 160ftlbs.Your HP numbers seem a little low for that setup,but still decent numbers.

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by LSVTEC 91 Civic &raquo;</TD></TR><TR><TD CLASS="quote">I'd like to see your AFR...</TD></TR></TABLE>

i'll try to source it..and will post it here.

 

It's also a corrected graph, but not 100% sure as the RPM's are cut off. If the lines don't cross at 5252 then it's corrected.

Grab some numbers from the chart and plug them into this:
HP = Torque x RPM ÷ 5252

and see if it jives.

 

graph isnt corrected..the reason i cut off the graph bcos the rpm isnt tally to what the actual RPM of the engine so people wont get confused. the guy at the dyno told me its bcos of the transmission mods i did which doesnt make sense to me..if u want i will post the whole uncut graph..

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by rapid_roy &raquo;</TD></TR><TR><TD CLASS="quote">It's also a corrected graph, but not 100% sure as the RPM's are cut off. If the lines don't cross at 5252 then it's corrected.

Grab some numbers from the chart and plug them into this:
HP = Torque x RPM ÷ 5252

and see if it jives.</TD></TR></TABLE>

i dont have the chance to scan it yet but i did calculation base on your formula n fornula actually work!

with the rpm at approx 4950rpm X the torque is approx 160 and divide the 5252..i got the answer of 150.799 which is what actual shown on my graph.i will post them later..