How do I tell what trim the wheel is???
Sent the wrong turbo NOT a .63/.60 like i wanted...
It's actually a .60 comp and .48 ex. (Garrett T3 turbo) But I have no clue what trim it is. Im hoping its either 50 or 60 trim wheel.
It's a Garrett and it has a A/R .60 on the comp side and it has a M11 on it.
.48 exhaust.
Anyone know what this thing is?
A strange thing I found. It actuallys says "Garrett A/R .60 M11" on the side (normal). It also says ".60" inside of the OUTLET (not inlet) hole on the compressor housing where the air is blow out. Would this mean it's a 60 trim??
I appologize for these questions, but if i would have been sent the correct turbo in the first place i wouldn't have to ask them.
Thanks for the replies
Dan
It's actually a .60 comp and .48 ex. (Garrett T3 turbo) But I have no clue what trim it is. Im hoping its either 50 or 60 trim wheel.
It's a Garrett and it has a A/R .60 on the comp side and it has a M11 on it.
.48 exhaust.
Anyone know what this thing is?
A strange thing I found. It actuallys says "Garrett A/R .60 M11" on the side (normal). It also says ".60" inside of the OUTLET (not inlet) hole on the compressor housing where the air is blow out. Would this mean it's a 60 trim??
I appologize for these questions, but if i would have been sent the correct turbo in the first place i wouldn't have to ask them.

Thanks for the replies
Dan
the onnly way to tell what trim it is, is to remove the compressor housing, and get a measurement of the wheel size (the small section [top] and the larger sectoin [bottom]) then you can determine the trim size.
well, the housing is 60 A/R, but you can find the wheel trim by measuring the diameter of the inducer ( smaller wheel, on top)
is it a T3/4E or B ? E has 6 blades, B has 7 blades on the compressor wheels
stan
is it a T3/4E or B ? E has 6 blades, B has 7 blades on the compressor wheels
stan
<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by intekragsr »</TD></TR><TR><TD CLASS="quote">square the inducer and exuder, and divide by the smaller number. thats your trim....correct me im wrong. </TD></TR></TABLE>
okay, you're making me think here...do I add the inducer and major diameter, square it then divide by the smaller number ?
I tried that and it did not came out to be the right number.
stan
okay, you're making me think here...do I add the inducer and major diameter, square it then divide by the smaller number ?
I tried that and it did not came out to be the right number.
stan
((minor diameter/major diameter)^2)*100
glad i could help
it's also etched in the compressor housing outlet. It says .60 so i would assume 60
glad i could helpit's also etched in the compressor housing outlet. It says .60 so i would assume 60
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okay, hopefully you're not mistaken by all this info...lemme try to clarify it
two things:
Compressor HOUSING is measure in A/R, in this case is 60 A/R (Area/Radius) this measure the size of the housing itself.
Compressor WHEEL is measure in trim (mm), which is the diameter of the wheel itself.
A/R number is achieve by dividing the Area of any circle in the path of the housing to the distance of the center of that circle to the center of the turbo cartridge ( Radius). This number represent the capacity (I am lacking terms here
) of the housing and it's capacity to flow. Since compressor housing have gradual pattern of design, you can take any measurement of the circle and radius at ANY given path and it will give you the same number of A/R. The larger the circle, the longer the distance from the center cartridge.
Trim, is the size of the wheel, this will determine the ABility to flow.
So your compressor housing is a 60A/R, but the wheel trim is what to be determine by measure the diameter of the smaller wheel ( the inducer) by a calipers or a ruler
stan
two things:
Compressor HOUSING is measure in A/R, in this case is 60 A/R (Area/Radius) this measure the size of the housing itself.
Compressor WHEEL is measure in trim (mm), which is the diameter of the wheel itself.
A/R number is achieve by dividing the Area of any circle in the path of the housing to the distance of the center of that circle to the center of the turbo cartridge ( Radius). This number represent the capacity (I am lacking terms here
) of the housing and it's capacity to flow. Since compressor housing have gradual pattern of design, you can take any measurement of the circle and radius at ANY given path and it will give you the same number of A/R. The larger the circle, the longer the distance from the center cartridge.Trim, is the size of the wheel, this will determine the ABility to flow.
So your compressor housing is a 60A/R, but the wheel trim is what to be determine by measure the diameter of the smaller wheel ( the inducer) by a calipers or a ruler
stan
this works too 
[(minor wheel diameter)x(minor wheel diameter) / (major wheel diameter)x (major wheel diameter) ] x 100= trim
T04E 60
[(2.290)(2.290)/(2.950)(2.950)] x 100= trim
(5.2441/8.7025) x 100= trim
.6026 x 100 = trim
60= trim

[(minor wheel diameter)x(minor wheel diameter) / (major wheel diameter)x (major wheel diameter) ] x 100= trim
T04E 60
[(2.290)(2.290)/(2.950)(2.950)] x 100= trim
(5.2441/8.7025) x 100= trim
.6026 x 100 = trim
60= trim
<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by intekragsr »</TD></TR><TR><TD CLASS="quote">this works too 
[(minor wheel diameter)x(minor wheel diameter) / (major wheel diameter)x (major wheel diameter) ] x 100= trim
T04E 60
[(2.290)(2.290)/(2.950)(2.950)] x 100= trim
(5.2441/8.7025) x 100= trim
.6026 x 100 = trim
60= trim
</TD></TR></TABLE>
I just measured it LOL screw the math heheheh
stan

[(minor wheel diameter)x(minor wheel diameter) / (major wheel diameter)x (major wheel diameter) ] x 100= trim
T04E 60
[(2.290)(2.290)/(2.950)(2.950)] x 100= trim
(5.2441/8.7025) x 100= trim
.6026 x 100 = trim
60= trim
</TD></TR></TABLE>
I just measured it LOL screw the math heheheh
stan
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