what exactly would 84mm sleeves put a b16a2 at as of the size(liters)? i dont think it would be quite as big as a stock b18c1, would it?

 

nope i htink it would like you at i think 1.9ltrs
Not excatly sure, so dont quote me on that.

 

i cant find it anywhere, and i have no clue how to figure it out

 

nope im worng on that cuz that would be a 84mm bore and a 92mm stroke. that would give you 1.97ltrs

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by tgh99si &raquo;</TD></TR><TR><TD CLASS="quote">what exactly would 84mm sleeves put a b16a2 at as of the size(liters)? i dont think it would be quite as big as a stock b18c1, would it?</TD></TR></TABLE>

somewhere near 1.79l

 

alright 1.79l, um can you tell me how i can figure this out? i know it has to do with the stroke too.

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by tgh99si &raquo;</TD></TR><TR><TD CLASS="quote">alright 1.79l, um can you tell me how i can figure this out? i know it has to do with the stroke too.</TD></TR></TABLE>

I think it's something like this...can't remember the conversion from cc's to liters though...

displacement= stroke*area cylinder*amount of cylinders
area of cylinder = (Pi*D^2)/4

for a b16

stroke = 77mm (7.7cm)
area = (Pi*8.1^2)/4

*4=~1590cc

 

All you're doing is finding out the volume of a cylinder, and multiplying it by 4. (Pi*r^2)*L*# of cylinders. With an 84MM bore and a 77MM stroke (I don't know where the hell that guy got 92MM from) you get 1707.06CC's.

R = radius of the cylinder, half of the bore. L = length of cylinder, which is your stroke. All the Si units are on a powers system. 1 meter is 100 centimeters. 100 centimeters is 1000MM, etc, etc. So 1 liter = 1000 CC's.


Modified by boosted92 at 5:05 PM 2/5/2004

 

awesome, thats cool. thanks guys