... corrected mass flow question... CMf = WHP... why or why not?
06-19-2003, 02:04 PM
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... corrected mass flow question... CMf = WHP... why or why not?
i have been working with compressor maps, trying to match a turbo to my setup to see if i could reach my goals... and i was wondering if corrected mass flow can be used as a good estimation of power output... i have read that CMf x 10 equals whp... so for example 40 lb/min would equate to about 400whp... is this accurate method of estimation or not?... if not, what is a better way to estimate?... thanks...
07-14-2003, 11:53 AM
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Re: ... corrected mass flow question... CMf = WHP... why or why not? (Zero2Sixty)
<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Zero2Sixty »</TD></TR><TR><TD CLASS="quote">just go to rc website, there method is pretty acurate.</TD></TR></TABLE>
... ummm... okay... i didnt find anything on rc's website pertaining to compressor maps... but thanks for the bump...
... anyone else?...
... ummm... okay... i didnt find anything on rc's website pertaining to compressor maps... but thanks for the bump...
... anyone else?...
07-14-2003, 12:09 PM
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Re: ... corrected mass flow question... CMf = WHP... why or why not? (1.8T_EG)
Using the lb X 10 method is a pretty good way of seeing how much horsepower you will be able to make. hmmm *thinking*
07-14-2003, 03:29 PM
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Re: ... corrected mass flow question... CMf = WHP... why or why not? (1.8T_EG)
pm me with your setup..
I can determine hp & tq figures for any level of boost
if given the NA dyno plot, and if there will be no changes to the motor setup .
I can determine hp & tq figures for any level of boost
if given the NA dyno plot, and if there will be no changes to the motor setup .
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