I have been searching, but have yet to find a 1 ohm stable sub. Are there any out there that are resonably priced?

 

There is no such thing as a 1ohm stable sub, but there are however 1ohm stable amps. Maybe you're looking for a sub with an impedance of 1 ohm?

 

Whats the point in a 1 ohm stable amp if there are no one ohm stable subs? Whats the difference in a impedence of 1 ohm and stble 1 ohm?

 

You can find a DVC 2 ohm sub wich can be wired down to 1 ohm or 2 DVC 4 ohm subs that can be wired down to 1 ohm. The lower the impeadance you put at the amp the less the amp has to work which is how you get more power. However, the amp also gets much more hot and can over work and blow out. So saying an amp is 2ohm stable means the least recomended impeadance you should have on your subs is 2 ohms because if you go lower the amp will most likey fry. One other thing Im not sure if tomany people know is when you bridge a 2 chanel amp each side of the amp sees half the impeadance. So if the amps is 2 ohm stable and you wire it up at 2 ohms bridged each side of the amp is only seeing 1 ohm. There for your running the risk of blowing your amp.

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote &raquo;</TD></TR><TR><TD CLASS="quote">The lower the impeadance you put at the amp the less the amp has to work which is how you get more power. However, the amp also gets much more hot and can over work and blow out. </TD></TR></TABLE>

You just totally contradicted yourself...

 

I realized that however i dint know how to explain it. Okay the higher the ohm load the harder the amp works the lower the ohm load the easier but if its to low it will allow the amp to do to much work and over work its self. Is that better? Either way you know what i mean

 

The higher the impedance, the less strain the amp has.

More heat=more stress

Can't defy the laws of thermodynamics

 

I agree, Now explain why if theres less strain the amp cant produce as much power.

 

P=(V^2)/(R)

P=power
V=voltage
R=resistance


Voltage potential stays constant in this case. When you decrease resistance, you increase output. When you increase resistance, you decrease output. I guess you can think of impedance is a restriction. The less restriction you have, the more current will flow, which means more output is coming out of that amp. Usually amps will decrease in efficiency as the ohm load decreases. Heat has to go somewhere and if it's not efficient at 4ohm as 8ohm, the amp will run hotter. Can't really change the heatsink to fit all loads.

 

GSteg is right on with that, I think were saying the same thing in two different ways. Hope this isnt all kinds of confusing.

 

ok I think I get kinda what you mean. You can have a mono 1ohm amp, hook 2 dvc 2 ohm subs up the right way and make them run at 1 ohm. And stable means what it can run at safely.

 

Exactly!

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by NACvicSi &raquo;</TD></TR><TR><TD CLASS="quote">ok I think I get kinda what you mean. You can have a mono 1ohm amp, hook 2 dvc 2 ohm subs up the right way and make them run at 1 ohm. And stable means what it can run at safely.</TD></TR></TABLE> No not...
<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by MLD211 &raquo;</TD></TR><TR><TD CLASS="quote">Exactly!</TD></TR></TABLE> 2 DVC 2 ohm subs can be wired for a .5 ohm or 2 ohm load, or even an 8 ohm load, however 2 DVC 4 ohm subs can be wired for a 1 ohm or 8 ohm load, or even 16 ohms, or you can wire 1 DVC 2 ohm sub for a 1 ohm or 4 ohm load or 1 DVC 4 ohm sub for a 2 ohm or 8 ohm load, but there is no way to wire 2 DVC 2 ohm subs for a 1 ohm load. 94

 

fcm is right. I didnt read that post close enough. That wasnt the point of the thread though. I think he got the point just didn't do the right math.

 

i lol at people who think they know caraudio... need help aim me at smokem240 and fcm.. you know whats up

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by GSteg &raquo;</TD></TR><TR><TD CLASS="quote">P=(V^2)/(R)

P=power
V=voltage
R=resistance


Voltage potential stays constant in this case. When you decrease resistance, you increase output. When you increase resistance, you decrease output. I guess you can think of impedance is a restriction. The less restriction you have, the more current will flow, which means more output is coming out of that amp. Usually amps will decrease in efficiency as the ohm load decreases. Heat has to go somewhere and if it's not efficient at 4ohm as 8ohm, the amp will run hotter. Can't really change the heatsink to fit all loads. </TD></TR></TABLE>
For dropping impedence this is correct. but it's impedence not resistance Impedence=reactance+resistance but we all know what you meant to say...

When you bridge an amp the voltage doubles. The + and - you see on an amp doesn't really meany anything. They are put there so you get the phase correct.

On an amplifier you have two amplifiers. One is the power supply it converts the 12Vdc to 27Vac twice the other is the audio amplifier. Now run it through a bridge rectifier and you end up with +27Vdc and -27Vdc. You should notice something they are 180 degrees apart.
So in order to keep the phase correct manufacturers put + and - on the terminal. You will notice if you take your amp apart one + terminal and one - termanal are the same. They do the phase inversion for you inside the amp. That's why when you bridge it you use a + from one side and a - from the other. Effectively using the entire power supply voltage of 54v!!