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Resistor box question

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Old Feb 14, 2004 | 11:57 PM
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Project92Hatch's Avatar
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Default Resistor box question

Well ive seen all the wiring instructions on this. But I dont really get it. Here are two links I found that show you how to do this.
http://www.hondata.com/techinjectorwiring.html
http://www.fourthgenhatch.com/mpfi.html

Now I dont really get it tho. There are two wires on each injector, One wire from each injector goes to one wire on the resistor box. Then this is were i get confused. The other wire stays connected right. But then you have to cut four other wires and wire them all together and splice them into the red power wire in the resistor box. What are the other four wires? There are 8 wires total coming from the injectors. 4 go to the resistor box and the other 4 stay connected that go to the ecu. What wires are the other 4 that go into the one power wire?



Do you basically cut all 8 of those wires going into that plug and connect the 4 injector wires to the resistor box and the other 4 to the red power wire. Or no?


Modified by Project92Hatch at 9:43 AM 2/15/2004
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Old Feb 15, 2004 | 11:57 AM
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Default Re: Resistor box question (Project92Hatch)

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Old Feb 15, 2004 | 06:20 PM
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Default Re: Resistor box question (Project92Hatch)

these are the four wires for the injectors that go between the resistor box and 12v power source. not that hard, really...
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Old Feb 15, 2004 | 06:26 PM
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Default Re: Resistor box question (hondatim)

Ummm thanks but that doesnt really help paint a picture of what im confused about.
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Old Feb 15, 2004 | 06:34 PM
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Default Re: Resistor box question (Project92Hatch)

Ok, let's try to put this another way...

You have 4 wires from the injectors that go to the resistor box. you also have the 4 wires from the injectors that go to the ECU. then you have 4 wires from the resistor box that goes to 1 wire 12v power source.
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Old Feb 16, 2004 | 05:56 AM
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Default Re: Resistor box question (Project92Hatch)

Picture this: 4 of the 8 injectors wires are really already tied together (which go to +12v and are Yel/Blk)....but you still see 8 of'em. The other 4 wires, individually, lead back to the ECU. The ECU grounds the injector; it fires.

The 4 Yel/Blk wires will be cut from the injector clip, ends will be stripped (the end that is still tied to +12v), tied together and then soldered to the 'individual' lead of the resistor box (which ever gets the +12v).

The 'other' 4 wires on the resistor box now get soldered onto the 'now-cut' Yel/Blk wires of the injectors.

Note: Unsure of resistor box wire colors, so I used "individual' and 'other' for them.

Inside the box, picture 4 resistors. One lead of each resistor are all tied together (this is the 'individual' lead) while the other four leads are the 'other' wires. All your doing is wiring a resistor INLINE with each injector.

Hopefully that was painted well.
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Old Feb 16, 2004 | 01:07 PM
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Default Re: Resistor box question (EE_Chris)

Ok thanks guys that helped alot. Let me see if I got this. You cut the yellow/black wires from the injectors. Then you take the yellow/black wire that isnt connected to the injector and put all four together and splice them into the "red" power wire. Then you take the yellow/black wire that is still connected to the injector and run each one to an induvidaul wire on the resistor box. Is this right?
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Old Feb 16, 2004 | 01:42 PM
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Default

this might help too https://honda-tech.com/zerothread?id=517274
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Old Feb 16, 2004 | 01:54 PM
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Default Re: Resistor box question (Project92Hatch)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Project92Hatch &raquo;</TD></TR><TR><TD CLASS="quote">Ok thanks guys that helped alot. Let me see if I got this. You cut the yellow/black wires from the injectors. Then you take the yellow/black wire that isnt connected to the injector and put all four together and splice them into the "red" power wire. Then you take the yellow/black wire that is still connected to the injector and run each one to an induvidaul wire on the resistor box. Is this right?</TD></TR></TABLE>
Yes
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Old Feb 16, 2004 | 03:10 PM
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Default Re: Resistor box question (Project92Hatch)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Project92Hatch &raquo;</TD></TR><TR><TD CLASS="quote">Ok thanks guys that helped alot. Let me see if I got this. You cut the yellow/black wires from the injectors. Then you take the yellow/black wire that isnt connected to the injector and put all four together and splice them into the "red" power wire. Then you take the yellow/black wire that is still connected to the injector and run each one to an induvidaul wire on the resistor box. Is this right?</TD></TR></TABLE>

Correct indeed.
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Old Feb 16, 2004 | 03:46 PM
  #11  
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Default Re: Resistor box question (EE_Chris)

From what I hear, and I'll be doing this in a couple of days so...

Just get a voltmeter attach one side to either of the two wires on the injector. Then test every wire in those 8 that are on the harness near the master cylinder. If you don't get a hit then you got the wire on the injector that goes to the ECU.

Just move it to the 2nd of the two wires on that injector and re-test all of the wires on the harness near the master cylinder. When you get a hit, move that wire aside. it will be one of the wires that you will have to cut and solder into the resistor box.

Repeat this process until you've found all four wires. Once you've found all four, cut and solder them all to the single, usually red, 12v wire on one side of the resistor box. Wrap in electrical tape. On the opposite side of the the resistor box you will simply connect any of the four black wires to any of the four yellow wires, the order does not matter because they are essentially one wire at that point.

Viola.
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