pioneer TS-W301R
I want to build a box for my two pioneer ts-w301R subs. They are 12" in diameter and the suggested box size is 1.65cu.ft. I believe the dimension in inches should be
15-5/8" x 13" x 14" I want to make sure this is right. also what I want to do is make the box like this l O l l O l so the port is in the very mid and both subs will be ported through that hole. I appreciate any help and hopefully someone can tell me if my dimensions are correct.
15-5/8" x 13" x 14" I want to make sure this is right. also what I want to do is make the box like this l O l l O l so the port is in the very mid and both subs will be ported through that hole. I appreciate any help and hopefully someone can tell me if my dimensions are correct.
The dimensions you give will get you 1.6 cuft, outside the internal volume, [using 3/4" MDF] would be 1.18 cuft.
The other thing is your box dimensions are almost a cube, it will generate "standing waves" inside the box leading to cancellation, [a loss of output].
If it is your first time building a box I would agree with White Smoke build a sealed enclosure with no less then 2 cuft internal volume, no more then 4 cuft, recommended is 3 cuft gross, [two drives], install a divider in the box so each driver has it's own air space, angle at least one surface of the box.
94
The other thing is your box dimensions are almost a cube, it will generate "standing waves" inside the box leading to cancellation, [a loss of output].
If it is your first time building a box I would agree with White Smoke build a sealed enclosure with no less then 2 cuft internal volume, no more then 4 cuft, recommended is 3 cuft gross, [two drives], install a divider in the box so each driver has it's own air space, angle at least one surface of the box.
94
As White Smoke & FCM have stated, a sealed enclosure is the way to go with those subs.
And actually, I wouldn't bother building a box. Buy a premade box like this one: http://www.bestbuy.com/site/ol...59557
I have one of those in my car (only because I got it for like $30 when I worked at Best Buy
) and have my 10 year old JL 12" W0's in it, and they sound pretty damn good.
And actually, I wouldn't bother building a box. Buy a premade box like this one: http://www.bestbuy.com/site/ol...59557
I have one of those in my car (only because I got it for like $30 when I worked at Best Buy
) and have my 10 year old JL 12" W0's in it, and they sound pretty damn good.
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Match the angle to the back seat angle, so the box butts right up against the seat back.
The formula for volume is Height x Width x Depth.
Some parameters are "fixed" or max, EG; width of box, box has to fit between the shock towers so the outside width dimension can be no more then distance between the shock towers, [lets call that 32"] next would be height, it can be no lower then the outside diameter of the speakers, plus 1.5", [lets call that 14"].
You need an internal volume of 3 cuft x1728=5184 cuin.
Assuming you have an overall width of 32"-1.5"=30.5" and an overall height of 14"-1.5"=12.5" 30.5x12.5=381.25 divide that into the 5184 cuin you need and you get 13.5", [rounded off], meaning the depth of the box will be 13.5"+1.5"=15".
30.5x12.5x13.5=5146, well within the 10% +/- allowed for a sealed box.
For the angle the 13.5" depth can be 5" on top and 8.5" on the bottom, or any combination that adds up to 13.5".
What I will do is calculate the angle I need, cut my two end pieces and center divider, [I always use 1" MDF for end pieces and 3/4" for center divider.
All 3 of these pieces will be exactly the same in shape and size, [other then thickness, unless you use 1" for the divider also] the rest of the pieces, [top, bottom, back and front will screw into the ends and divider.
Once you have your ends you can easily calculate the width of the box.
EG; say the ends are 13.5' in height the bottom is 8.5" and the top is 5", 8.5+5=13.5" 13.5"x 13.5"=182.25 sqin, divide that into 5184=28.5", [rounded off] plus the thickness of the divider will be the width of the box.
94
The formula for volume is Height x Width x Depth.
Some parameters are "fixed" or max, EG; width of box, box has to fit between the shock towers so the outside width dimension can be no more then distance between the shock towers, [lets call that 32"] next would be height, it can be no lower then the outside diameter of the speakers, plus 1.5", [lets call that 14"].
You need an internal volume of 3 cuft x1728=5184 cuin.
Assuming you have an overall width of 32"-1.5"=30.5" and an overall height of 14"-1.5"=12.5" 30.5x12.5=381.25 divide that into the 5184 cuin you need and you get 13.5", [rounded off], meaning the depth of the box will be 13.5"+1.5"=15".
30.5x12.5x13.5=5146, well within the 10% +/- allowed for a sealed box.
For the angle the 13.5" depth can be 5" on top and 8.5" on the bottom, or any combination that adds up to 13.5".
What I will do is calculate the angle I need, cut my two end pieces and center divider, [I always use 1" MDF for end pieces and 3/4" for center divider.
All 3 of these pieces will be exactly the same in shape and size, [other then thickness, unless you use 1" for the divider also] the rest of the pieces, [top, bottom, back and front will screw into the ends and divider.
Once you have your ends you can easily calculate the width of the box.
EG; say the ends are 13.5' in height the bottom is 8.5" and the top is 5", 8.5+5=13.5" 13.5"x 13.5"=182.25 sqin, divide that into 5184=28.5", [rounded off] plus the thickness of the divider will be the width of the box.
94
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