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friend gave me a 10w0 . . no clue what amp i need.

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Old Sep 3, 2005 | 03:19 PM
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Default friend gave me a 10w0 . . no clue what amp i need.

i'll begin by saying my audio knowledge is basic at best. . i read the faq but could barely get anything i needed from it so im forced to make my own topic, i apologize for my lack of understanding in advance.

so i have a 10w0 in a sealed box. i need an amp for it. jl audio recommends 125w continuous power. is that the number thats most important? they dont make any mono amps that power that low, so i'll have to bride a 2channel amp like this

alpine Alpine MRP-T220


140 watts bridged.

its more than recommended but i wont be blasting any music.


is my logic sound? does this set up make sense?

o yea, my current car audio is a pioneer 6400 deck kenwood coaxials in the front and alpine coaxials in the back
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Old Sep 3, 2005 | 03:50 PM
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sounds good...
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Old Sep 3, 2005 | 06:25 PM
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Default Re: (Slain)

i just checked the specs on the sub, it's normal imedence is at 12 ohms


the alpine can only give 140W at 4 ohms


does this mean i need a more powerful amp? im guessing all of this just on some basic physics principles i know. my subwoofer has high resistance so will I need more power to make a sound out of it?
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Old Sep 3, 2005 | 09:15 PM
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Default Re: (mr poo)

Can you send me the link where you found the specs. Ive searched and i cant find it. Then maybe I can help.
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Old Sep 3, 2005 | 10:36 PM
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Default Re: (romoracing)

the specs on the sub? they're at http://www.jlaudio.com look under their discontinued subwoofers and download the pdf file

if u want specs of the amp its on http://www.crutchfield.com just put in a search for it
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Old Sep 4, 2005 | 08:55 AM
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Default Re: (mr poo)

Hahaha, Sorry im used to looking on the left and not in the middle on the JL site. That alpine amp wont cut it. Look at the JL 1000/1 amp. Because the Driver(sub) is at 12 ohms and that needs power. The 1000/1 is:
1000 W RMS @ 1.5 ohm - 4 ohm (11V-14.5V) so most likely youll have at least 125 watts to work with. If there is alittle more it wont really hurt the sub. My home theater speakers are 8 ohms and the rms is 450 and im sending 500 w. rms and so far so good.
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Old Sep 4, 2005 | 09:16 AM
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Default Re: (mr poo)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by mr poo &raquo;</TD></TR><TR><TD CLASS="quote">the specs on the sub? they're at http://www.jlaudio.com look under their discontinued subwoofers and download the pdf file

if u want specs of the amp its on http://www.crutchfield.com just put in a search for it</TD></TR></TABLE> Do you know for sure that you have the 12 ohm and not the 4 or 8 ohm? http://mobile.jlaudio.com/pdfs/10_12_15W0_MAN.pdf and the amp is 140W x 1 into 4 ohms @ 14.4V 20Hz to 20kHz at 8 ohms it would be 70w x 1 and @ 12 ohm it will be around 45W http://www.alpine-usa.com/ not the sub for that amp or not the amp for that sub. but I would check the imp. of the sub, for that amp to work you need a 4 ohm sub, or if it is a 12 ohm sub, you will need an amp that will make 125W at 12 ohms, that would be about about 375W into 4 ohms like the Alpine MRD-M605 250W x 1 @ 12V/600W x 1 @ 14.4V or the JL 300/2 300W x 1, JL e1400 320W x 1 @ 14.5V 94
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Old Sep 4, 2005 | 09:47 AM
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Default Re: (fcm)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by fcm &raquo;</TD></TR><TR><TD CLASS="quote"> Do you know for sure that you have the 12 ohm and not the 4 or 8 ohm? </TD></TR></TABLE>

if he is saying he has a 12ohm sub, it's probably a 12 ohm sub.

the subwoofer is probably from prefab cs310rw0 box, where it used three 12 ohm subwoofers wired in parallel for a 4 ohm load overall.

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Old Sep 4, 2005 | 10:11 AM
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Default Re: (dc24me)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by dc24me &raquo;</TD></TR><TR><TD CLASS="quote">

if he is saying he has a 12ohm sub, it's probably a 12 ohm sub.

the subwoofer is probably from prefab cs310rw0 box, where it used three 12 ohm subwoofers wired in parallel for a 4 ohm load overall.

</TD></TR></TABLE> That may be true, but if you don't ask you can't be sure, and if you have asked for clarification on a point as many times as I have, and have gotten a diff. answer, you would understand why I asked. I also gave him options if it was a 12 ohm sub. 94
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Old Sep 4, 2005 | 11:56 AM
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Default Re: (dc24me)

yes it is a 12 ohm sub. my friend got a deal on a box with 3 10s in it and he only had space to run 2 so he gave me the extra
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Old Sep 4, 2005 | 08:25 PM
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Default Re: (mr poo)

how are the W0's? ive herd the 6 and 7's but never the 0's.
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Old Sep 4, 2005 | 09:52 PM
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Default Re: (showtime23)

You best luck is to call alpine or jl audio and ask what there amps can do at 12 ohms. For a car the most should be a 8 ohm sub, 12 is over kill. But good luck!!
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Old Sep 4, 2005 | 10:31 PM
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Default Re: (romoracing)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by romoracing &raquo;</TD></TR><TR><TD CLASS="quote">You best luck is to call alpine or jl audio and ask what there amps can do at 12 ohms. For a car the most should be a 8 ohm sub, 12 is over kill. But good luck!!</TD></TR></TABLE>

i think i might just give up on this sub and sell it, could you explaint to me how it would work wiring in "parallel" and wat amp is needed?
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Old Sep 5, 2005 | 08:50 AM
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Default Re: (mr poo)

You can sell it and get something like this:
http://www.crutchfield.com/S-0...252W3
My neighbor has it and its pretty nice!!


Also I think this might help:
http://www.crutchfield.com/S-0....html

Or:

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by mr poo &raquo;</TD></TR><TR><TD CLASS="quote">You have a one-channel amplifier which is rated at 400 watts RMS at 4 ohms, but can handle a 2 ohm load. You have two subwoofers which are each rated at 50-250 watts RMS. The subwoofers have a rated impedance level of 4 ohms.

First, you have to make sure that the amplifier is capable of operating under a 2 ohm load safely. When purchasing one, that information should be provided.

Next, you need to calculate the load impedance of the amplifier to the subwoofers. This is shown in the equation below.

Resistance total = one divided by the quantity of the reciprocals of the resistance of each speaker added together

R total = 1 / (1 / R1 + 1 / R2)

R total = 1 / ( 1 / 4 + 1 / 4)

R total = 1 / ( 1 / 2)

R total = 2



Just as in the series example, you have to find out how much power will be delivered to each speaker to determine whether this amp is suited for the subwoofers being used. Remember that the power output of the amplifier will change because there is a different load being placed on the amplifier. The amplifier will send a different amount of power to a speaker in a 2 ohm load than it will under a 4 ohm load. The total output of the channel must be calculated first, then the output power can be calculated to each speaker.



Total Power output to speakers:

P total = Rated amp power x (impedance of output power amp is rated at / the actual impedance of the load from the speakers)

If the amp is rated at 400 watts at 4 ohms, and a 2 ohm load is placed on the amp, then the power output of a 2 ohm load will be 800 watts.

P total = 400 x (4/2)

P total = 800 watts



Power to each speaker:

Power = P total x (actual impedance of the load from the speakers / rated impedance of speaker)

If the total power to the speakers in a 2 ohm load is 800 watts, and the speakers are both rated at 4 ohms a piece, then each speaker will receive 400 watts of power. The equation differs from the series equation in that as stated before, when the impedance level decreases the power going to the speakers increases.

Power = 800 x (2 / 4)

Power = 400 watts



Basically, without the complicated equations, if you cut the resistance of the power going from the amplifier to the subwoofer by two, then the total power is inversely related so the power will increase by a factor of two. The resulting power will then be distributed between the two speakers so the power going to each will be half that of the power output. The equations are given to help clarify more complicated hook-ups. </TD></TR></TABLE>
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