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trying to figure out what size rods to use with tech43 pistons, 92 mill crank in GSR

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Old Mar 15, 2005 | 03:43 AM
  #1  
Blind-Fashion's Avatar
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Default trying to figure out what size rods to use with tech43 pistons, 92 mill crank in GSR

https://honda-tech.com/zerothread?id=951003

there is a link to his pistons and SOME specs

I'm not wonderfull on ANY of my math and i wont claim to be, i'm just trying to find out what rod size to use with this setup. I want a good r/s ratio because this is going to be a road race car but i wont to get some more dispacment.


So, just for the record,

I want to use the Tech43 pistons (.851 comp height) in a gsr block ( 8.347 deck height ) and a 92mm crank ( 3.62204 )

I need more help, this will be my first none oem length motor :-).. lol SOMEONE HELP MEE!!


this is just some of the info i had jotted down, if anyone can help, or if this will help

3.50393 89mm crank
3.62204 92mm crank
.11811 3mm bigger than 89mm crank
.349 differance between b16 and gsr deck height
5.045 rod legnth on stock pistons with 92 mill crank
5.394 Stock LS rod length
5.62489 added deck hight, minus .11811 for the 92 mill crank
5.743 Added Deck height


no matter what math i do, it never equals within .001 - .003 of the stock gsr deck height ( 8.347 )

I got all of my info from http://raceseek.com/honda_specs.htm


Thanks in advance, please no flamming, this is my first wack at it!

-Josh
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Old Mar 15, 2005 | 04:07 AM
  #2  
NJIN BUILDR's Avatar
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Default Re: trying to figure out what size rods to use with tech43 pistons, 92 mill crank in GSR (Blind Fash

Block height-compression height-1/2 crank stroke=rod length
8.347-.851-(1/2 3.622) 1.811= 5.685 rod length
This gives you a zero deck height.My advice would be a 5.660" length.This will allow a .005" block resurface.This will give you a .020" deck height for adequate piston to head clearance.
Glenn
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Old Mar 15, 2005 | 05:12 AM
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CompressionFed's Avatar
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Default Re: trying to figure out what size rods to use with tech43 pistons, 92 mill crank in GSR (Blind Fash

Good explanation
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Old Mar 15, 2005 | 06:09 AM
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Default

ahh ok then, i see where i went wrong, thanks for the help!
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