How does one convert from degrees to inches, since many people refer to toe measured this way ex. 1/8" toe out, as opposed to 1º toe out? Since alignment seems to be measured from the rim, it seems ridiculous to specify settings in inches, since this is dependent on the wheel (and tire) size, if I'm understanding this.

If I know that my toe setting (as measured on an alignment rack) is -.023º and I have a 195/60/14 tire (outside diameter ~23") do I say (23"*3.14)/360 = 1º in this respect, so that this would be -.005"?!

Or is the measurement in inches contingent on some invisible path of suspension movement/ adjustment?

I'm just wondering because I have front toe readings of -.07ºL and -.10ºR, when the negative toe is easily visible and somewhere around 1/4" total toe out (yes, too much) and converting the degree measurement (from the alignment rack) shows a very, very tiny amount of negative toe.

 

So, does anyone know this? How would 1º toe out be equated to X" toe out, or vice versa?

 

I'm guessing the toe distance is based on the rim diameter, not the tread diameter. So in your case...

Toe = sin(angle) * 14"
Toe = sin(0.1deg)*14" = 0.0244"

angle = asin(toe/14")
angle = asin(0.25/14) = 1 degree

Something doesn't add up. Are you sure you're "seeing" toe, or maybe camber?