Question about comperssion ratio?
I understand c.r. and the higher the cr the more hp you get, but what i dont understand is the set up of the numbers ex. 10.6.1....... I know this may sound stupid but i would really like to know what all the numbers mean so when someone ask a question ill know the answer for sure.
Lets take a 10 to 1 compression ratio. The 1 is the volume of the combustion chamber at TDC. 10 is the swept volume plus the combustion chamber volume (volume of the complete cylinder at BDC).
Example:
Combustion chamber vol. of 50cc
Complete cylinder vol. of 500cc
Divide 500cc by 50cc = 10 or (10 to 1)
50cc x 10 = 500cc per cylinder
500cc x 4 cylinders = 2000cc x .001 = 2.0L
[Modified by Quiz, 6:34 PM 1/15/2003]
Example:
Combustion chamber vol. of 50cc
Complete cylinder vol. of 500cc
Divide 500cc by 50cc = 10 or (10 to 1)
50cc x 10 = 500cc per cylinder
500cc x 4 cylinders = 2000cc x .001 = 2.0L
[Modified by Quiz, 6:34 PM 1/15/2003]
Thanks now i know, so if it is 10.5.1 it's basically 10x1=10 and the other number like 4 or 5 we'll say 4 times that 10 ='s 40cc per cylinder. Times 4 so 40x4=160. Then times 160x10=1600cc.................B16, D16, ZC16..Thanks.
Antwaine
Antwaine
No
This 10.5.1 you give as an example should read 10.5 to 1 c/r
The 50cc and 500cc were just arbitrary numbers I gave you for examples of volume.
If you had a 50cc combustion chamber with 10.5 to 1 c/r then you would have 525cc BDC cylinder volume
525cc x 4 cyl = 2100cc x .001 = 2.1l
This 10.5.1 you give as an example should read 10.5 to 1 c/r
The 50cc and 500cc were just arbitrary numbers I gave you for examples of volume.
If you had a 50cc combustion chamber with 10.5 to 1 c/r then you would have 525cc BDC cylinder volume
525cc x 4 cyl = 2100cc x .001 = 2.1l
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10.5 represents how many times you could fit the volume of 1 combustion chamber (TDC volume) in the complete cylinder volume at BDC
[Modified by Quiz, 5:02 PM 1/16/2003]
[Modified by Quiz, 5:02 PM 1/16/2003]
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