Lambda is @ 12.4:1
550cc injectors are @ 2.22 ms
How can I lean it out? Tables?
(I had a semi-base tune interrupted due to failing starter.)

 

You have A LOT of reading to do. Lambda is read in voltage and not ratios. Read the SManager help files and it should be enough for you to get going but don't blame them when you toast your engine.

 

lol, harsh words, but honestly I agree with using them.

if you're that clueless on what is going on and what to do about it, pay a tuner to tune your car before you blow it up.

 

Just saying that the car is running rich is super vague. Post a datalog.

 

Don't post anything, spend the next solid month reading how to tune first, or pay a professional to do it for you if you don't have the budget for a new engine.
There's a manual in my sig, it's for a different program but it's the same process.

 

I thought lambda was a percentage of stoichiometric?

 

Yes, you are right - thanks for correcting me on that. I knew what I meant but put in voltage for some reason instead of percent. Both lambda and AFR readings are derived from sensor voltage haha... The span of AFR is about 10:1 ratio and Lambda is about +/- 32% from stioch which equals 100% (aka a value of 1.00).

 

Well, if you have an Innovate controller you can program the the voltage to match lambda if you want to keep it simple. and less accurate.
But only AEM linear controllers span from 10-20AFR, Innovate and others can read much richer.

Etymologically Lambda actually equals 30, but in chemistry Lambda has no set value. It's just used to symbolize the result of a fraction, x/1=L.
Whatever mixture would result in perfect combustion of all the compounds (air & fuel) is considered the stoich denominator (1). Then you compare your reading of the actual combustion over stoich. Lambda is the answer.
Just some Bill Nye tangent action for you.