i read the write up here on ht and it was great. but it says under the desoldering areas to remove j12. the question is, do i remove it and not replace it with anything or does another resistor go in its place?

 

When removing j12 you do not replace it with anything, you simply cut it out or desolder it.

 

are u going to be rtp or datalogging?if not u can just leave it in it wont effect anything.

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by zccr-xsi &raquo;</TD></TR><TR><TD CLASS="quote">are u going to be rtp or datalogging?if not u can just leave it in it wont effect anything.</TD></TR></TABLE>

yep, it basically unlocks/locks the ecu data.

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by 98vtec &raquo;</TD></TR><TR><TD CLASS="quote">

yep, it basically unlocks/locks the ecu data.</TD></TR></TABLE>

It doesn't really lock the data.

You can log with J12 still in tact. But it is slower.

 

ive never even been able to connect to the ecu to datalog with it connected..

which ems are you referring to?

 

Ditto. Crome doesn't let me log with j12 intact.

I think Uber is the only software that let you do that.

 

J12 in = half duplex
J12 out = full duplex

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by ef92b &raquo;</TD></TR><TR><TD CLASS="quote">J12 in = half duplex
J12 out = full duplex</TD></TR></TABLE>

good to know. Never tried it with ectune but it wouldnt let me do anything with j12 intact when i ran crome.