Gsr motor all ring lands atleast 8 cracks each, spun rod jbearings all.. On the crank one juirnal is toast. what are my options for cranks,, I all ready have gsr rods and pistons ,motor cleaned up fine with .010, any ls, b16 cranks work and what will need done
thanks

 

you might be able to get the crank fixed that it to a machine shop and see what they say

 

i dont recommend getting anything done to the crank once its scored up... the bearings never seat right.

 

Based on my past experience with scoring a rod journal, you'll probably need to have that one rod journal ground down and use an undersized bearing (.010" or .025" are the common sizes). If that's really what will happen, you'd be better off with buying a good condition, used crank.

When that journal was scored, the bearing wasn't spun, just chewed up.

 

so what will it take to make a ls crank work, what size rods and what will that give me fro displacement.
Thanks

 

To use the LS crank, you need to use conrods for the LS.

There's also the option to use GS-R length rods, but you need to use custom pistons with the wrist pin moved up to keep the piston-to-deck height reasonably at or below the deck.

Oil squirters might also be an issue too, so you'll need to check the clearance against the crank counterweight and the piston pin boss area and piston skirt.

If you need to plug the oil squirters, you can have somebody chop and weld the tips shut or drill/tap the block to plug it with a NPT plug.

- Displacement -

81.5mm bore (if you use aftermarket forged pistons):

81.5mm / 2 = 40.75mm

40.75mm (^2) = 1660.5625 mm^2

1660.5625mm^2 x 3.14 = 5214.16625mm^2 (this is the total surface area of the bore)

We multiply by the height (stroke) to get the total volume of one cylinder. In this case, the crank stroke length is 89mm.

5214.16625mm^2 x 89mm = 464060.79625mm^3

Convert from cubic millimeters to cubic centimeters (which is the same as a milliliter) by dividing by a conversion factor of 10^3 = 1000.

464060.79625mm^3 x (1/1000) = 464.06079625cm^3 = 464.06079625mL

464.06079625mL is the volume of just one cylinder, so we multiply by the number of cylinder we have (4).

464.06079625mL x 4 = 1856.243185mL

If you used a std 81mm bore piston, then it would be 1834mL.

If you used a 81.25mm OS OEM Honda piston, then it would be 1845mL.

 

you are the man. Now I know
Thanks