quick ohm's question
05-27-2003, 06:42 PM
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Re: quick ohm's question (Ludeboi)
You can run it at 1.5 but it will overheat after a while. How are you getting 1.5 ohms? You should make sure that 1.5 is the impedence that you are running because many people get confused over ohm's law.
05-27-2003, 07:12 PM
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Re: quick ohm's question (nsxxtreme)
<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by nsxxtreme »</TD></TR><TR><TD CLASS="quote">How did you determine it was 2 ohm stable? vteg pretty much summed it up though.</TD></TR></TABLE>
he probably looked it up in the manual or some sort
he probably looked it up in the manual or some sort
05-27-2003, 08:37 PM
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Re: quick ohm's question (Ludeboi)
I have gotten away with doing what you are trying to do it just depends on the amp. I know nothing about memphis. I would just try it and pay close attention to how hot it gets. If it gets really hot you will shorten the life of the transistors inside. You may also trip the built in short circuit protection because the load may be to low. I have ran 1/2 ohm to Autotek Mean machines before no sweat.
You could also run your speakers in series then parallel for a 6 ohm load but this defeats the purpose of what you are trying to do.
You could also run your speakers in series then parallel for a 6 ohm load but this defeats the purpose of what you are trying to do.
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05-29-2003, 01:21 PM
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Re: quick ohm's question (Bigphlip)
<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Bigphlip »</TD></TR><TR><TD CLASS="quote">because many people get confused over ohm's law.</TD></TR></TABLE>
Definitely. Ohms are probably one of the most difficult concepts ive had to understand
Definitely. Ohms are probably one of the most difficult concepts ive had to understand
05-29-2003, 01:51 PM
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Re: quick ohm's question (RAF LTD. 2)
Don't get me as stupid, But Could someone sum up ohms law. What causes certain subs and amps to be certain ohms? I never really got the series/parallel idea, I know the increase or decrease the ohms load, right? How does that work?
05-29-2003, 02:17 PM
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Re: quick ohm's question (Torridcivic)
All ohms law does is express voltage as a function of current I=V/R The units of the impedence are in ohms named after Georg Simon Ohm.
I think for what you are trying to do you would more follow Kirchoffs law.
For series impedence you just add them 4ohm plus 4ohm = 8ohm
For parallel impedence you use this equation 1/(1/4ohm + 1/4ohm)=2ohms
If you have more Impedences you keep usining the same equation just add more impedences in the denominator. 1/(1/4ohm + 1/4ohm + 1/4ohm +ect) = 1.33Ohms
Many short cuts have been made here to keep it simple
I think for what you are trying to do you would more follow Kirchoffs law.
For series impedence you just add them 4ohm plus 4ohm = 8ohm
For parallel impedence you use this equation 1/(1/4ohm + 1/4ohm)=2ohms
If you have more Impedences you keep usining the same equation just add more impedences in the denominator. 1/(1/4ohm + 1/4ohm + 1/4ohm +ect) = 1.33Ohms
Many short cuts have been made here to keep it simple
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