anyone know??

 

Off-topic- nice to see a fellow Missourian on the boards who has a CRX...Where is Scott City? I am located in Columbia, MO. (Recently moved from Tampa, FL)

 

I think you mean .040. As if you bored if over 40,000 you would have turned the whole engine block and whatever is standing next to it into dust.

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by FourthGenHatch &raquo;</TD></TR><TR><TD CLASS="quote">I think you mean .040. As if you bored if over 40,000 you would have turned the whole engine block and whatever is standing next to it into dust.</TD></TR></TABLE>

LMAO.

 

There is not a real easy answer to this question.
You have to use algebra with pie and other measurements on this one. I suggest popping this one in tech, (engine theory) and see what THEY come up with.

Scott

 

1634cc

 

A very large paperweight or door stop?

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by virginia_dude &raquo;</TD></TR><TR><TD CLASS="quote">A very large paperweight or door stop?</TD></TR></TABLE>
maximum recommended overbore is 0.5mm which is approximately 0.020"

 

hey im hatchin from missouri.. st joseph to be exact

 

Scott city is about 2 hours south from missouri. Like 10 minutes from Cape Girardeau. So if you are familiar with either of those 2 it should help you. I just got my block bored to that a lil while back and i wanted to see what it was. Iwas thinking it was close to a 1.7l but i was not sure by how much. Head has als been ported & polished along with being shaved. Block has been bored and milled. Umm i am also goin to be runnin a 4-1 header i got off of ebay with a d16y8 intake manifold with an h22a4 throttle body. We do not have a 1/4 mile track but we do have an 1/8th, so i am hopin with proper traction that i will be runnin like low nines in the 1/8th. My car is more of a handling car though, tein ha coilovers, front upper, front lower, rear upper, rear lower, all are neuspeed except the front lower, then some suspension techniques sways front and rear. Handles like a god.

Matt

 

LOL i knew that reply would be in here before i opened the thread

 

Wow...another missouri person..sweetness! Here in Missouri, I think we're seriously lacking in tuning shops, and tracks. We have nothing here in Columbia (that I know of...) as far as tuning shops OR tracks go. I've seen a few nice CRX's around here in Columbia, believe it or not. Oh well, I still see more 4 doors with altezza's

 

bore x bore x stroke x .7854 x # of cyl = displacement....

 

(pi*((bore/2)squared))*stroke) = Displacement of engine

listen to me not this guy /\

 

that is the dispalcement for a single cylinder, but your equation is more correct than the previous one.

 

yeah there are a lot of people in MO with CRXs. I know of a bunch around Mid Mo area. New Bloomfield, JC, Columbia....there are quite a few.

 

I've seen only 3 or 4 modified CRX's here in columbia. I know one of the owners..the other 2-3 I don't know.

The other CRX's that I have seen have been stock. Where are you located?

 

formulas are the same - pi*radius(squared)
is equal to
pi*diameter(squared)/4

 

I am in Jefferson City. There is a shop in New Bloomfield and they have several crxs. I have seen like 4 here in JC that are done up. Mine looks stocks but has a motor swap with a D16z. There is another crx down here that has a LS motor.

 

Is there any tuning shops up there in Jeff City? There is NONE around here. My B16A swap will be coming a bit later than expected (I am trying to complete the turbo kit and various other things BEFORE the engine goes in..believe it or not), but once it's in, I want to have it tuned. Any input would be appreciated.

Also, what do you all have up there as far as tracks go?

 

i am just curious as to how these equations actually work - cause unless i have done something wrong, neither one comes up anywhere near the right answer - i don't know the stroke on my civic motor, but do know the info on my old prelude motor. so, if the bore is 83mm, the stroke is 95, then these two equations are suppose to come up with how much displacement the motors put out, right? so my 2.1 liter motor puts out 2.1 liters of displacement. the first equation comes out to be 83x83x95x4 which equals 2,617,820. the second equation would be 3.14x(83/2)squaredx95 which equals 513,747.17. what is missing from this? those numbers do not tell me the liters of displacement without converting or something. what is missing? someone help me understand this one.

 

There are no tuning shops around here. In New Bloomfield there is a shop but I am unsure of the work they do. I think they are called AA motors. I know they sell cars but they also have several Rx7s and crxs that they run. Other than that most people around here work on their own cars or their buddies cars.

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Darton Sleeves &raquo;</TD></TR><TR><TD CLASS="quote">bore x bore x stroke x .7854 x # of cyl = displacement....</TD></TR></TABLE>

Please tell me your user ID has N O T H I N G to do with Darton sleeves.
I have never seen square shaped sleeves. Where did you learn that??

Since when is the area of a circle diameter X diameter??


EDIT:

I take back what I said.
His formula works, not the way I learned in college, but it sure works.
sorry.


Modified by The new Spaceballs at 6:31 PM 10/12/2003

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by The new Spaceballs &raquo;</TD></TR><TR><TD CLASS="quote">

Please tell me your user ID has N O T H I N G to do with Darton sleeves.
I have never seen square shaped sleeves. Where did you learn that??

Since when is the area of a circle diameter X diameter??</TD></TR></TABLE>

Actually Darton's right for however many cylinders there are, all he did was simplify some of the parameters so one could plug in values quicker. The second formula by mntuner2 is correct but for only one cylinder volume.

Volume of a cylinder is the area of of a circle times the height:
= "Pie are squared" * Height
= Pi * Radius * Radius * Height

If the Radius is 1/2 the Diameter, and the Diameter is the Bore. And Height is the Stroke, this becomes:
= Pi * (Bore/2) * (Bore/2) * Stroke
= Pi * [(Bore * Bore)/4] * Stroke &lt;- this is basically what mntuner2 got, but it only solves for one cylinder

Darton simplified the Pi and 1/4 fraction and rounded up:
= ~3.1416 * [(Bore * Bore)/4] * Stroke
= ~0.7854 * Bore * Bore * Stroke

Then Darton factored in the # of cylinders for total displacement:
= ~0.7854 * Bore * Bore * Stroke * # of cyl.

Seriously, you guys who jumped on him should plug some numbers into both equations and see what you get.

So to the original poster, "40-thousandths" = 40/1000 = 0.040" = 1.016mm overbore. I'm not sure what 1.5 engine you have, so I'm unsure of the original bore & stroke. But just add 1.016mm to your factory bore and plug that into the equation.


Modified by XrcR6 at 7:49 PM 10/13/2003

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Swift &raquo;</TD></TR><TR><TD CLASS="quote">that is the dispalcement for a single cylinder.</TD></TR></TABLE>

Sorry peeps. I was more focused on writing the formula for the volume of a cylinder.