How much faster would a 2dr be racing a 4dr sedan with the same setup and driver...etc.

 

same weight?

if they are the same weight use this one:

4dr wins by __ lenghts =[4x^2+4x]/[4y^2+4y-2]

if they are different used this one:

2dr wins by __ lenghts =[2x^4+2x]/[2y^4+2y-4]

y is 2dr weight is in ounces
x is 4dr weight is in kilograms


Modified by cluelessmale at 1:58 PM 1/2/2008

 

^^^ lol

 

haha, rofl

 

I could have used you my senior year for calculus wtf ! ! !

thats funny stuff

 

good formula tried this very close!

 

awesome

 

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by cluelessmale &raquo;</TD></TR><TR><TD CLASS="quote">same weight?

if they are the same weight use this one:

4dr wins by __ lenghts =[4x^2+4x]/[4y^2+4y-2]

if they are different used this one:

2dr wins by __ lenghts =[2x^4+2x]/[2y^4+2y-4]

y is 2dr weight is in ounces
x is 4dr weight is in kilograms


Modified by cluelessmale at 1:58 PM 1/2/2008</TD></TR></TABLE>

so 3dr is faster then...

 

What about a 5 door?

I'm sure that a 4dr pick-up would be much faster because it has a longer wheel base and would be easier to drive at 330mph, much the same as a TF car.

After all, we all know bigger is better...

May be this a question for rotodee...doesn't he race a 4dr blue car...

 

I think I got the 2nd one wrong, X should be Y and Y should be X.

It makes the numbers look more right.


Corrected:

if they are the same weight use this one:

4dr wins by __ lenghts =[4x^2+4x]/[4y^2+4y-2]

if they are different used this one:

2dr wins by __ lenghts =[2y^4+2y]/[2x^4+2x-4]


Hopefully this helps who ever started this post