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Type R pressureplate and 6 puck disc - will it hold the power?

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Old 09-21-2003, 09:48 PM
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Default Type R pressureplate and 6 puck disc - will it hold the power?

I had an xtreme pressure plate and 6 puck disc, but i think the 2600lb clamp load of the xtreme plate just caused the clutch to goto hell... the pressure plate friction side it pretty word, as is the flywheel side.

so im thinking of downgrading the pressure plate to either a heavy duty or a Type R one... im pretty strapped for cash as it is, so im leaning towards a type R one. will the type R pp even fit my LS flywheel? My plans are 320whp which would be about 260ft/lb of torque if that helps.

-ryan
Old 09-21-2003, 09:51 PM
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Default Re: Type R pressureplate and 6 puck disc - will it hold the power? (tegasaurus)

I don;t think the Type R pressure plate will hold at all at that horsepower level, the MOST important is usually the pressure plate, that is why most are super stiff BUT like the Twin disk clutches the disc really comes into play and is MOST important. You can run around with the stock ITR pressure plate and it will work with the LS flywheek no problem BUT I think it will slip, the disc will help some but the pressure plate is not strong enough IMHO> Good luck though.
Old 09-21-2003, 10:47 PM
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Default Re: Type R pressureplate and 6 puck disc - will it hold the power? (Boostfed)

yeah... it'll work... but almost a waste of clutch with a pp as weak as a stock ITR (comparatively)
Old 09-21-2003, 11:14 PM
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Default Re: Type R pressureplate and 6 puck disc - will it hold the power? (X2BOARD)

Well here's how i figure it...

the XTSS (xtreme pp and street disc) will hold 319 ft/lb, the XTR6 (same PP with 6 puck disc) will hold 408 ft/lb
319/408 = .78186

The HDSS (Heavy duty pp and street disc) will hold 243 ft/lb, the HDR6 (same PP with 6 puck disc) will hold 311 ft/lb
243/311 = .78186

That's a 78% increase (in both situations) because of the change in discs.
================================================== ==
Now if we use the same formula and compare pressureplates, it comes out to be closely the same linear change.
311/408 = .76225

That's a 76% increase (in both situations) because of the change in Pressure plate


So basically getting the disc increases it's holding capacity more than the stiffer pressure plate. The XT pressure plate rated at 100% stiffer over stock is known as to have a 2600lb diaphram. the HD pressureplate is rated at 55% stiffer over stock.

100/2600 = 55/X

Cross multiplying gives me that the HD presure plate is about a 1430 pound diaphram

Now here's where you guys come into play... Can someone please tell me the diaphram rate of a stock R pressure plate so i can figure out how much this clutch can potentially hold
Old 09-21-2003, 11:25 PM
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Default Re: Type R pressureplate and 6 puck disc - will it hold the power? (tegasaurus)

DAMN! The scientific route!!!!!!! Good post.
Old 09-22-2003, 12:21 AM
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Default Re: Type R pressureplate and 6 puck disc - will it hold the power? (Boostfed)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Boostfed &raquo;</TD></TR><TR><TD CLASS="quote">DAMN! The scientific route!!!!!!! Good post. </TD></TR></TABLE>

well... I'm going to assume that the type R pressure plate would be about an 1100 lbs diaphram/clamp load.

If that holds true, then 1100 lb pp with 6 puck should yield around 274 ft/lb holding capacity.

I totally forgot how i came up with that number, but its either 265 or 274 ft/lb

hrm.... time for me to lay off the speed
Old 09-22-2003, 08:59 AM
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Default Re: Type R pressureplate and 6 puck disc - will it hold the power? (tegasaurus)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by tegasaurus &raquo;</TD></TR><TR><TD CLASS="quote">Well here's how i figure it...

the XTSS (xtreme pp and street disc) will hold 319 ft/lb, the XTR6 (same PP with 6 puck disc) will hold 408 ft/lb
319/408 = .78186

The HDSS (Heavy duty pp and street disc) will hold 243 ft/lb, the HDR6 (same PP with 6 puck disc) will hold 311 ft/lb
243/311 = .78186

That's a 78% increase (in both situations) because of the change in discs.
================================================== ==
Now if we use the same formula and compare pressureplates, it comes out to be closely the same linear change.
311/408 = .76225

That's a 76% increase (in both situations) because of the change in Pressure plate


So basically getting the disc increases it's holding capacity more than the stiffer pressure plate. The XT pressure plate rated at 100% stiffer over stock is known as to have a 2600lb diaphram. the HD pressureplate is rated at 55% stiffer over stock.

100/2600 = 55/X

Cross multiplying gives me that the HD presure plate is about a 1430 pound diaphram

Now here's where you guys come into play... Can someone please tell me the diaphram rate of a stock R pressure plate so i can figure out how much this clutch can potentially hold </TD></TR></TABLE>

Your math is very flawed.

319/408 = .78186 is NOT a 78% increase. 319 is 78% of 408....

a 78% increase over 319ft lbs would be as follows:
319 + (319 * .78) = 567.82 ft lbs. THAT is a 78% increase.

The correct way to calculate this would be:
(408-319) / 319 = 27.9% increase in clamping force.

Using the correct increase, 319ft lbs + new disk (27.9%increase):
319 + (319 + 27.9) = 408!

Next, your 311 / 408 is wrong too.
408-311 = 97 ft/lb increase.
97/311 = 31.1%
the 408ft/lb plate is a 31.1% increase in clamping force.

Hopefully all this corrected math will do you some good in finishing your caluclations!

IMHO, don't use a stock pp. Use a stock clutch with an extreme pp, but never the other way around!

Old 09-22-2003, 11:55 AM
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Default Re: Type R pressureplate and 6 puck disc - will it hold the power? (Johnyquest)

<TABLE WIDTH="90%" CELLSPACING=0 CELLPADDING=0 ALIGN=CENTER><TR><TD>Quote, originally posted by Johnyquest &raquo;</TD></TR><TR><TD CLASS="quote">

Your math is very flawed.

319/408 = .78186 is NOT a 78% increase. 319 is 78% of 408....

a 78% increase over 319ft lbs would be as follows:
319 + (319 * .78) = 567.82 ft lbs. THAT is a 78% increase.

The correct way to calculate this would be:
(408-319) / 319 = 27.9% increase in clamping force.

Using the correct increase, 319ft lbs + new disk (27.9%increase):
319 + (319 + 27.9) = 408!

Next, your 311 / 408 is wrong too.
408-311 = 97 ft/lb increase.
97/311 = 31.1%
the 408ft/lb plate is a 31.1% increase in clamping force.

Hopefully all this corrected math will do you some good in finishing your caluclations!

IMHO, don't use a stock pp. Use a stock clutch with an extreme pp, but never the other way around!

</TD></TR></TABLE>

yeah, i knew where iw as going with the math but it was all in my head, i just didn't know exactly how to write it down (going on 27 hours awake with 3hours of sleep).

I've heard of people using the type R pp and 6 puck and it working very well.

oh well, i'll probably go for the HD and 6 puck.
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